Poles = number of poles of your motor. So, for example, if you have a 4 pole motor on 60 Hz then RPM=60*(2/4)*60=1800 rpm.

## How is motor calculation?

A watt (W) is a unit of power defined as one Joule per second. For a DC source the calculation is simply the voltage times the current: **W = V x A**. However, determining the power in watts for an AC source must include the power factor (PF), so W = V x A x PF for AC systems.

## Which is better 2 pole or 4 pole motor?

A **2 pole motor** has high speed due to less number of poles. Conversely, a 4 pole motor has low speed due to more number of poles. A 2 pole motor is more efficient on the flip side, a 4 poles motor is less efficient. A 2 pole motor has more RPM value; on the other side, the 4 poles motor has fewer revolutions per minute.

## What is a 4 pole 3 phase motor?

. For example, for a four-pole, three-phase motor, = 4 and = 1,500 RPM (for = 50 Hz) and 1,800 RPM (for. = 60 Hz) synchronous speed. The number of magnetic poles, , is equal to the number of coil groups **per phase**.

## What is 120 in motor speed formula?

The equation for calculating synchronous speed is: **S = 120 f/P speed = constant (120) times frequency of power source (60 Hz) divided by number of poles used in the motor (P)**.

## How can we increase the RPM of motor?

By **increasing the voltage of the armature**, it produces more magnetic forces to overcome the field magnet, increasing the rpm. By increasing the field current, more magnetic fields opposing the motion are produced, at the same time more cemf is produced reducing the armature voltage, decreasing the rpm.

## What is the formula for work done?

To express this concept mathematically, the work W is equal to the force f times the distance d, or W = fd. If the force is being exerted at an angle θ to the displacement, the work done is **W = fd cos θ**.

## How is rated power calculated?

Calculate power rating in KVA when you know voltage and output resistance. Use the formula: **P(KVA) = (V^2/R)/1000 where R is resistance in ohms**. For example, if V is 120 volts and R is 50 ohms, P(KVA) = V^2/R/1000 = (14400/50)/1000 = 288/1000 = 0.288 KVA.

## What is the efficiency formula?

Efficiency is often measured as the ratio of useful output to total input, which can be expressed with the mathematical formula **r=P/C**, where P is the amount of useful output (“product”) produced per the amount C (“cost”) of resources consumed.